利用如图装置进行燃烧条件的探究。试管①中充满氮气,试管②③中充满氧气,升温至40℃,仅观察到②中的白磷燃烧。下列叙述错误的是( )
【分析】根据化学反应的原理、燃烧的条件以及实验现象来分析。
【解答】解:A、实验①白磷不燃烧是因为白磷不接触氧气,实验②中白磷能与氧气接触能燃烧,所以对比实验①②可验证燃烧需要氧气,故A正确;
B、实验③中红磷不燃烧是因为温度为达到着火点,对比实验②③可推知着火点高低:红磷>白磷,故B正确;
C、可燃物的着火点是物质固有的属性,一般不能改变,故C错误;
D、①③两支试管内的白磷和红磷均未反应,可回收再利用,故D正确。
故选:C。
【点评】本考点是用白磷探究燃烧的条件,属于实验方法和过程的探究。这类探究实验要具体问题具体分析,根据设计的步骤中不同的现象去思考、去探究,从而回答题目给出的问题。本考点主要出现在填空题和实验题中。
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请在字典中查一下这个词。
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我叫托尼· 史密斯, 史密斯是我的姓。
我们在课上回答问题时应该起立
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