当前位置:首页学历类中考化学->利用如图装置进行燃烧条件的探究。试管①中充满氮气,试管②③中

利用如图装置进行燃烧条件的探究。试管①中充满氮气,试管②③中充满氧气,升温至40℃,仅观察到②中的白磷燃烧。下列叙述错误的是(  )

image.png


  • A.由实验①②可验证燃烧需要氧气
  • B.由实验②③可推知着火点高低:红磷>白磷
  • C.利用水浴控温可调节可燃物的着火点
  • D.①③两支试管内的白磷和红磷可回收再利用
答案: C
本题解析:

【分析】根据化学反应的原理、燃烧的条件以及实验现象来分析。

【解答】解:A、实验白磷不燃烧是因为白磷不接触氧气,实验中白磷能与氧气接触能燃烧,所以对比实验①②可验证燃烧需要氧气,故A正确;

B、实验中红磷不燃烧是因为温度为达到着火点,对比实验②③可推知着火点高低:红磷>白磷,故B正确;

C、可燃物的着火点是物质固有的属性,一般不能改变,故C错误;

D、①③两支试管内的白磷和红磷均未反应,可回收再利用,故D正确。

故选:C。

【点评】本考点是用白磷探究燃烧的条件,属于实验方法和过程的探究。这类探究实验要具体问题具体分析,根据设计的步骤中不同的现象去思考、去探究,从而回答题目给出的问题。本考点主要出现在填空题和实验题中。


更新时间:2022-04-14 14:06
纠错

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