当前位置:首页学历类中考化学->下列叙述正确的是(  )

下列叙述正确的是(  )


  • A.
  • B.工业上分离液态空气得到O2的变化属于化学变化
  • C.自然界中植物通过光合作用吸收CO2,释放O2
  • D.人体呼出的气体中CO2的含量比O2高
答案: C
本题解析:

【分析】A、根据高锰酸钾在加热条件下生成锰酸钾、二氧化锰和氧气,进行分析判断。

B、工业上分离液态空气制取氧气的原理,进行分析判断。

C、根据自然界中植物通过光合作用的原理,进行分析判断。

D、根据人体呼出的气体的成分,进行分析判断。

【解答】解:A、该化学方程式缺少反应条件,正确的化学方程式为

image.png故选项说法错误。

B、工业上分离液态空气得到O2,利用的液态氮和液态氧沸点的不同,没有新物质生成,属于物理变化,故选项说法错误。

C、自然界中植物通过光合作用吸收CO2,释放O2,故选项说法正确。

D、人体呼出的气体中CO2的含量占4.5%左右,氧气含量为16%左右,人体呼出的气体中CO2的含量比O2低的多,故选项说法错误。

故选:C。

【点评】本题难度不大,了解氧气的工业制法、光合作用的原理、人体呼出的气体的成分等是正确解答本题的关键。


更新时间:2022-04-14 14:05
纠错

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